If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(2)^(-2)
{root[2][1/2]}
2*x^3+1*x^2+3*x+7 = 7;x
x
(10)^(-1.5)
{root[2][4/3]}
| 3r=-2r | | -3-d/6=-1 | | 4r=r | | 3k^2-2k-13=-5 | | 12+c=15.50 | | -3x-8y=-5 | | t^2-16t+28=0 | | y=11.96(x-4)+1.99 | | -5i(7i-4)= | | b+2=4.8 | | 40=x(x+2) | | 2x-10+65-1x=180 | | 4y=-3-x | | 6(2-x)=30 | | 18=6k-9-3k | | y-4x+1=0 | | 4+8x-12=3+3x+18 | | x+2+x-8+x+7+x-3+x+6+x-4=180 | | V^2-7r-8=0 | | 3.4+4=d | | -6(1+3x)+4=40-4x | | 8(x-.25)=4(2x-.5) | | 4x+4=2+10 | | 10-2x+3x=4-5x | | 4+2.2=s | | y=(x-0)(x-30)(x-60)(x-90)(x-120) | | 6(1+3x)+4=40-4x | | 4k^2+15=17k | | 12x+12=5x+1 | | 0=ln(x/5) | | -6u+30=2(u-5) | | 5+2u=-1 |